tag:blogger.com,1999:blog-1106826179205248419.post8618462452616919548..comments2024-03-19T12:41:26.427+02:00Comments on Blame It On The Voices: Answer this questionbiotvhttp://www.blogger.com/profile/05398287905592847113noreply@blogger.comBlogger11125tag:blogger.com,1999:blog-1106826179205248419.post-69010610494716590912012-02-07T20:27:11.767+02:002012-02-07T20:27:11.767+02:00What is the diversity of the book Knick knack patt...What is the diversity of the book Knick knack patty whackAnonymousnoreply@blogger.comtag:blogger.com,1999:blog-1106826179205248419.post-18804622620070708782011-11-02T20:13:18.464+02:002011-11-02T20:13:18.464+02:00to every mate who answered here- first READ THE IN...to every mate who answered here- first READ THE INSTRUCTIONS<br />then<br />the answer is 0..<br />let me start from the beginning<br />we don't know which of these is the correct answer, so the probability of the answer being A (or D as they have same values) is 1/3 and the probability of us choosing A is 1/4 thus the probability of us being correct if answer is A is 1/3*1/4. similar applies for B,C and D. summing the probabilities we get (1/3*1/4)+(1/3*1/4)+(1/3*1/4)+(1/3*1/4= 1/3 or 33.33%.<br />now 33.33% is the correct solution to this problem, but if you read the question carefully you'll see it asks us to pick a choice out of the 4. now as 33.33% is not in the options we can never anser it correct, thus our probability being 0!<br />voilarishabh sharmahttps://www.facebook.com/rishabh49noreply@blogger.comtag:blogger.com,1999:blog-1106826179205248419.post-81161966886614607912011-10-30T13:12:36.141+02:002011-10-30T13:12:36.141+02:00What question? They don't ask you a question, ...What question? They don't ask you a question, so how can you determine the probability of being right? None of the answers is possible.Anonymousnoreply@blogger.comtag:blogger.com,1999:blog-1106826179205248419.post-18895353000849301992011-10-30T02:34:36.238+03:002011-10-30T02:34:36.238+03:00this is similar to the liar-paradoxthis is similar to the liar-paradoxAnonymousnoreply@blogger.comtag:blogger.com,1999:blog-1106826179205248419.post-71787074124341915682011-10-29T12:13:18.465+03:002011-10-29T12:13:18.465+03:00Because 25% is listed twice, you have a 50% chance...Because 25% is listed twice, you have a 50% chance to be correct making B the right answer, therefore reducing the chance to be correct to 25% making A & D the right answers, therefore raising the chance to be correct to 50% and so and so... It is a paradox and the chance that you will be correct is 0% regardless the 4 choices and the percentage they show. After all, the question asks for a percentage as a final output, it doesn't limit you to the 4 choices as the only answers.Anonymousnoreply@blogger.comtag:blogger.com,1999:blog-1106826179205248419.post-6046221830593252722011-10-29T04:51:40.859+03:002011-10-29T04:51:40.859+03:00if two out of four answers are the same, then neit...if two out of four answers are the same, then neither is correct.<br />so only B and C are possible.<br />so that's 50/50.<br />therefore, B.Anonymousnoreply@blogger.comtag:blogger.com,1999:blog-1106826179205248419.post-17491574976590312042011-10-29T04:42:06.871+03:002011-10-29T04:42:06.871+03:00B.B.Anonymousnoreply@blogger.comtag:blogger.com,1999:blog-1106826179205248419.post-33958682465633291872011-10-29T02:30:18.182+03:002011-10-29T02:30:18.182+03:0025%25%Pablo Nuñezhttps://www.blogger.com/profile/14340092480853137366noreply@blogger.comtag:blogger.com,1999:blog-1106826179205248419.post-21969944951676104002011-10-29T01:36:03.491+03:002011-10-29T01:36:03.491+03:00TrueTrueAnonymousnoreply@blogger.comtag:blogger.com,1999:blog-1106826179205248419.post-79408326110622671292011-10-29T01:19:33.068+03:002011-10-29T01:19:33.068+03:00@Anon, No, because if you'd be right 50% of th...@Anon, No, because if you'd be right 50% of the time, then half of the answers must be 50%.Anonymousnoreply@blogger.comtag:blogger.com,1999:blog-1106826179205248419.post-81368948405427899092011-10-28T22:23:21.891+03:002011-10-28T22:23:21.891+03:00B.B.Anonymousnoreply@blogger.com